Dear children .... try all the question papers . If u have any doubt, pls comment
Qn Pool Trignometry
Kerala X First term 2012
first termQP2013(2)
first termQP2013 (1)
first termQP2013(3)
first termQP2013(4)
Kerala X First Term Page 1
Kerala X First Term Page 2
Kerala X First Term Page 3
Kerala First Term Page 4
first term (CBSE 2013)
First term 2011 (CBSE X)
First term (CBSE X - old qn paper)
Linear equations (CBSE)
Second degree equations
Question Pool (Circles)
Qn Pool Trignometry
Kerala X First term 2012
first termQP2013(2)
first termQP2013 (1)
first termQP2013(3)
first termQP2013(4)
Kerala X First Term Page 1
Kerala X First Term Page 2
Kerala X First Term Page 3
Kerala First Term Page 4
first term (CBSE 2013)
First term 2011 (CBSE X)
First term (CBSE X - old qn paper)
Linear equations (CBSE)
Second degree equations
Question Pool (Circles)
Sir how to solve 8th Question?
ReplyDeleteKerala X First Term Page 1
The triangle with ratio 3:4:5 will be a right angled triangle
DeleteYes, good job Rahul .... The triangle with 3 : 4 : 5 is a right triangle. There for hypotenuse will be the diameter. The whole circle is divided into 3 arcs. The Longest one is a semicircle and the other two together make another semi circle. the ratio of central angles will be 1: 1
DeleteSir, in the latest paper..4th question? :/
ReplyDeletealso 6th A and B
Delete@ Udhas ... 4th .. angle A = 33, therefore angle B = 90 -33 = 57. Angle d is also equal to 57 because they are angles in the same segment.
Delete6th .... AC = 4 CD = 2, DB = 3 { AC X CB = 20 and AD X DB = 18 }
6 A is yet to complete. it is from tangents
Sir what are tangents
ReplyDeleteTangent is the line touching the circle at one point only ......... it is not there for tis exam
DeleteSIR, IS THR ONLY TRIGONOMETRY WORKSHEET?
ReplyDeleteXAVIER
CLASS: 10 H(CBSE)
in pair of linear equation, last 4 qns r missing
ReplyDelete